Grouping like terms, we get 2n + 1 = 27We need to find 2 integers, n and n + 1, who have a sum = 27

n + (n + 1) = 27

2n + 1 - 1 = 27 - 1

2n

2n = 26

2n |

2 |

= |

26 |

2 |

= |

26 |

2 |

n =

Now, since we found our first integer, our 2nd integer is just one greater:

(n + 1) = 13 + 1

(n + 1) =

Since 13 and 14 are both consecutive integers and their sum is 27, we have our answer.