Point 1: (x_{1} =
_{1} =

Point 2: (x_{2} =
_{2} =

Determine the line equation that has a slope of 4 containing the point (x

We know that the standard line equation is y = mx + b. Rearranging that equation to solve for b, we get b = y - mx. Using the point that you entered = (3, 2) and the slope (m) = 4 that you entered, let's plug in those values and evaluate:

b = 2 - (4 * 3)

b = 2 - 12

b = -10

The y intercept is found by setting x = 0 in the line equation y = 4x - 10

y = 4(0) - 10

y =

y - y

y - 2 = 4(x - 3)

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