Show all factor pairs, prime factorization (factor tree), sum of factors (divisors), aliquot sum, and prime power decomposition of 143.

We do this by listing out all pairs of numbers greater than 0 and less than or equal to 143 who have a product equal to 143:

143 = 1 x 143

143 = 11 x 13

There are 2 factor pairs of 143.

1, 11, 13, 143

1, 11, 13, 143

Proper factors are all factors except for the number itself, in this case 143

1, 11, 13

Now, show the prime factorization (factor tree) for 143 by expressing it as the product of ALL prime numbers.

143 = 11 x 13 <--- 11 is a prime number

Next step is to reduce 13 to the product of prime numbers:

No prime power decomposition exists since there are no duplicate prime numbers in the prime factorization:

1 + 143 + 11 + 13 =

The aliquot sum is the sum of all the factors of a number except the number itself

1 + 11 + 13 =